NEET2003PhysicsUnits and DimensionsActual
Using mass (M) , length (L) , time (T) and current (A) as fundamental quantities, the dimension of permeability is
Options
- AM ⁻¹ LT ⁻² ~A
- BML ^2 ~T ⁻² ~A ⁻¹
- CMLT ⁻² ~A ⁻²
- DMLT ⁻¹ ~A ⁻¹ .
Correct answer
C. MLT ⁻² ~A ⁻²
Step-by-step solution
We know that the force per unit length of a wire carrying current due to another parallel wire carrying current is given by gathered d F d l = ₀ i₁ i₂ 2 d ₀= 2 d i₁ i₂ d F d l [ ₀ ]= [ L ] [ A ^2 ] [ MLT ⁻² ] [ L ] or [ ₀ ]= [ MLT ⁻² ] [ A ⁻² ]= [ MLT ⁻² ~A ⁻² ] . gathered