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JIPMER 2018
Exam
JIPMER
Year
2018
Subject
Physics
Chapter
Units and Dimensions

JIPMER 2018 · Physics · Units and Dimensions

Dimension of force is

Dimension of force is

Options

  1. A[M2 L1 T−1]\left[\mathrm{M}^2 \mathrm{~L}^1 \mathrm{~T}^{-1}\right]
  2. B[M1 L1 T−2]\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2}\right]
  3. C[M2 L−1 T−2]\left[\mathrm{M}^2 \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right]
  4. D[M1L1T−1]\left[M^1 L^1 T^{-1}\right]

Correct answer

B. [M1 L1 T−2]\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2}\right]

Step-by-step solution

\because F=ma\mathrm{F}=\mathrm{ma}=\mathrm{m} \frac{\mathrm{d}}{\mathrm{t}^2} \quad[∵a=dt2]\left[\because \mathrm{a}=\frac{\mathrm{d}}{\mathrm{t}^2}\right]F=[M][L][T]2∴F=[M1L1T−2]\begin{aligned} F & =\frac{[M][L]}{[T]^2} \\ \therefore \quad F & =\left[M^1 L^1 T^{-2}\right]\end{aligned}$$
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