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NEETPhysicsMotion in Two Dimensions

A particle is projected horizontally from a tower with velocity (10 ~m / s ). Taking (g=10 ~m / s ^2 ). Match the following two columns at time (t=1 ~s ). ( array |l|l|l|l| & Column I & & Column II (A) & Horizontal component of velocity & (p) & 5~ SI unit (B) & Vertical component of velocity & (q) & 10~ SI unit (C) & Horizontal displacement & (r) & 15~ SI unit (D) & Vertical displacement & (s) & 20~ SI unit array )

Options

  1. A(( A p , B q , C p , D s ) )
  2. B(( A r , B p , C q , D q ) )
  3. C(( A q , B r , C p , D q ) )
  4. D(( A s , B s , C p , D q ) )

Correct answer

A. (( A p , B q , C p , D s ) )

Step-by-step solution

A) Horizontal component of velocity: Since there's no horizontal acceleration, the horizontal velocity remains constant. (v_x=u_x=10 ~m / s . ) This matches (q) 10 SI unit. B) Vertical component of velocity: The vertical motion is under constant acceleration due to gravity. (v_y=u_y+a_y t=0+(10)(1)=10 ~m / s . ) This matches (q) 10 SI unit. - Note: Both A and B have the same value, which is common in physics problems. C) Horizontal displacement: Horizontal displacement is calculated using constant velocity. (x=u_x

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