NEET
- Exam
- NEET
- Subject
- Physics
- Chapter
- Motion in Two Dimensions
NEET · Physics · Motion in Two Dimensions
A particle is projected horizontally from a tower with velocity (10...
A particle is projected horizontally from a tower with velocity (10 / ). Taking (g=10 / \mathrm{s}^2). Match the following two columns at time (t=1 ).
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| Column I | Column II | ||
| (A) | Horizontal component of velocity | (p) | 5 SI unit |
| (B) | Vertical component of velocity | (q) | 10 SI unit |
| (C) | Horizontal displacement | (r) | 15 SI unit |
| (D) | Vertical displacement | (s) | 20 SI unit |
Options
- A((\mathrm{A} \rightarrow \mathrm{p}, \mathrm{B} \rightarrow \mathrm{q}, \mathrm{C} \rightarrow \mathrm{p}, \mathrm{D} \rightarrow \mathrm{s}))
- B((\mathrm{A} \rightarrow \mathrm{r}, \mathrm{B} \rightarrow \mathrm{p}, \mathrm{C} \rightarrow \mathrm{q}, \mathrm{D} \rightarrow \mathrm{q}))
- C((\mathrm{A} \rightarrow \mathrm{q}, \mathrm{B} \rightarrow \mathrm{r}, \mathrm{C} \rightarrow \mathrm{p}, \mathrm{D} \rightarrow \mathrm{q}))
- D((\mathrm{A} \rightarrow \mathrm{s}, \mathrm{B} \rightarrow \mathrm{s}, \mathrm{C} \rightarrow \mathrm{p}, \mathrm{D} \rightarrow \mathrm{q}))
Correct answer
A. ((\mathrm{A} \rightarrow \mathrm{p}, \mathrm{B} \rightarrow \mathrm{q}, \mathrm{C} \rightarrow \mathrm{p}, \mathrm{D} \rightarrow \mathrm{s}))
Step-by-step solution
A) Horizontal component of velocity:
Since there's no horizontal acceleration, the horizontal velocity remains constant.
(v_x=u_x=10 / )
This matches (q) 10 SI unit.
B) Vertical component of velocity:
The vertical motion is under constant acceleration due to gravity.
(v_y=u_y+a_y t=0+(10)(1)=10 / )
This matches (q) 10 SI unit.
- Note: Both A and B have the same value, which is common in physics problems.
C) Horizontal displacement:
Horizontal displacement is calculated using constant velocity.
(x=u_x t=(10)(1)=10 )
This matches (q) 10 SI unit.
- Note: A, B, and C all have the same value. This confirms our calculations.
D) Vertical displacement:
Vertical displacement is calculated using constant acceleration.
(y=u_y t+a_y t²=(0)(1)+10)(1)^2=0+5=5 )
This matches (p) 5 SI unit.
Final Matches
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- ()
- ()
- ()
This matches the configuration of option (1).