A body is projected horizontally from the top of a tower of height 180m with a velocity of 20 ms ^ - 1 . If acceleration due to gravity is 10 ms ^ - 2 then match the following. List-I List-II ( A ) Velocity of the body

Question

Quantrex Academy · Accepted Answer

Correct answer: C. A B C D IV II I III

The total horizontal displacement after one second is,

$x = {u}_{x}t = 20 \times 1 = 20m$ ,

Vertical displacement after one second is,

$y = {u}_{y}t + \dfrac{1}{2}g{t}^{2} = 0 + \dfrac{1}{2} \times 10\left(1\right) = 5m$

vertical velocity of the body after one second,

${v}_{y} = {u}_{y} + gt = 0 + 10 \times 1 = 10m{s}^{- 1}$

and velocity of the body after one second,

$\sqrt{{\left({v}_{y}\right)}^{2} + {\left({v}_{x}\right)}^{2}} = \sqrt{{10}^{2} + {20}^{2}} = \sqrt{500} = 22 . 4m{s}^{- 1}$

List-I		List-II
$( A )$	Velocity of the body after $1$ second $($ in ${ms}^{- 1}$ )	(I)	$5$
$( B )$	Horizontal displacement of the body after $1$ second (in meters)	(ii)	$20$
$( C )$	Vertical displacement of the body after $1$ second (in meters)	(iii)	$10$
$( D )$	Vertical velocity of the body after $1$ second $($ in ${ms}^{- 1}$ )	(iv)	$22 . 4$

$A$	$B$	$C$	$D$
$IV$	$II$	$III$	$I$

$A$	$B$	$C$	$D$
$I$	$II$	$III$	$IV$

$A$	$B$	$C$	$D$
$IV$	$II$	$I$	$III$

$A$	$B$	$C$	$D$
$II$	$IV$	$I$	$III$

A body is projected horizontally from the top of a tower of height...

Options

Correct answer

Step-by-step solution

More from Motion in Two Dimensions