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NEETPhysicsMotion in Two Dimensions

A body is projected horizontally from the top of a tower of height 180   m with a velocity of 20   ms - 1 . If acceleration due to gravity is 10   ms - 2 then match the following. List-I List-II ( A ) Velocity of the body after 1 second ( in ms - 1 ) (I) 5 ( B ) Horizontal displacement of the body after 1 second (in meters) (ii) 20 ( C ) Vertical displacement of the body after 1 second (in meters) (iii

Options

  1. AA B C D I V I I I I I I
  2. BA B C D I I I I I I I V
  3. CA B C D I V I I I I I I
  4. DA B C D I I I V I I I I

Correct answer

C. A B C D I V I I I I I I

Step-by-step solution

The total horizontal displacement after one second is, x = u x t = 20 × 1 = 20   m , Vertical displacement after one second is, y = u y t + 1 2 g t 2 = 0 + 1 2 × 10 1 = 5   m vertical velocity of the body after one second, v y = u y + g t = 0 + 10 × 1 = 10   m   s - 1 and velocity of the body after one second, v y 2 + v x 2 = 10 2 + 20 2 = 500 = 22 . 4   m   s - 1

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