A grasshopper leaps from the ground with an initial speed of 2 m/s at an angle of 60^ to the horizontal. The maximum vertical height cleared by the grasshopper during its leap is (take g = 10 m/s ^2 ):

Step-by-step solution

Given: initial speed u = 2 m/s , angle of projection = 60^ , and g = 10 m/s ^2 . The maximum height H attained by a projectile is given by the formula: H = u^2 ^2 2g Substitute the given values into the formula: 60^ = 3 2 ^2 60^ = 3 4 H = (2)^2 ( 3 4 ) 2 10 H = 4 3 4 20 H = 3 20 m To convert the height into centimeters, multiply by 100 : H = 3 20 100 cm = 15 cm . Answer: 15 cm