NEETPhysicsLaws of Motion
In the adjoining figure, the position time graph of a particle of mass 0.1 ~kg is shown. The impulse at t=2 ~s is
Options
- A0.02 ~kg ~m / s
- B0.1 ~kg ~m / s
- C0.2 ~kg ~m / s
- D0.4 ~kg ~m / s
Correct answer
C. 0.2 ~kg ~m / s
Step-by-step solution
From the graph we can say, upto t =2.0 ~s , the body moves with a constant velocity Slope of position-time graph = 4 2 =2 ~m / s After t =2.0 ~s , position-time graph is parallel to time axis i.e., body comes to rest. Change in velocity = dx =2 ~m / s Impulse = Change in momentum = mdv =0.1 2=0.2 ~kg ~m / s