In the adjoining figure, the position time graph of a particle of...

From the graph we can say, upto $\mathrm{t}=2.0 \mathrm{~s}$, the body moves with a constant velocity Slope of position-time graph $=\frac{4}{2}=2 \mathrm{~m} / \mathrm{s}$ After $\mathrm{t}=2.0 \mathrm{~s}$, position-time graph is parallel to time axis i.e., body comes to rest. $\therefore$ Change in velocity $=\mathrm{dx}=2 \mathrm{~m} / \mathrm{s}$ Impulse = Change in momentum $=\mathrm{mdv}=0.1 \times 2=0.2 \mathrm{~kg} \mathrm{~m} / \mathrm{s}$