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NEET
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Physics
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Center of Mass, Momentum and Collision

NEET · Physics · Center of Mass, Momentum and Collision

Four point masses are placed at four corners of a square of side 4...

Four point masses are placed at four corners of a square of side 4 m as shown in the figure. Match the following columns. (
Column IColumn II
(A)x−coordinateofcentreofmassof</td></tr><tr><td>4kgand2kg\begin{array}{l} x -coordinate of centre of mass of</td></tr><tr><td>4 kg and 2 kg \end{array}(p)(7 / 2) m
(B)x−coordinateofcentreofmassof</td></tr><tr><td>4kg,2kgand3kg\begin{array}{l} x -coordinate of centre of mass of</td></tr><tr><td>4 kg, 2 kg and 3 kg \end{array}(q)4 / 3 m
(C)y−coordinateofcentreofmassof</td></tr><tr><td>1kg,4kgand3kg\begin{array}{l} y -coordinate of centre of mass of</td></tr><tr><td>1 kg, 4 kg and 3 kg \end{array}(r)3 m
(D)y−coordinateofcentreofmassof</td></tr><tr><td>1kgand3kg\begin{array}{l} y -coordinate of centre of mass of</td></tr><tr><td>1 kg and 3 kg \end{array}(s)(20/9) m
)

Options

  1. AA−q,B−s,C−p,D−rA-q, B-s, C-p, D-r
  2. BA−p,B−q,C−s,D−rA-p, B-q, C-s, D-r
  3. CA−r,B−s,C−q,D−pA-r, B-s, C-q, D-p
  4. DA−s,B−q,C−r,D−pA-s, B-q, C-r, D-p

Correct answer

A. A−q,B−s,C−p,D−rA-q, B-s, C-p, D-r

Step-by-step solution

Formulas: - x-coordinate of COM: (x=\Sigma(m i x i) / \Sigma(m i)) - yy-coordinate of COM: (\bar{y}=\Sigma(m iyi)\mathrm{i} \mathrm{yi})/ \Sigma(m i)\mathrm{i})) Corner coordinates used above. A. x-coordinate of COM of 4 kg and 2 kg : - Masses at (0,4)(0,4) and ((4,0) → x^{-}=(4 ⋅\cdot0+2 ⋅\cdot4) /(4+2)=8 / 6=4 / 3  m\mathrm{~m}). B. x-coordinate of COM of (4  kg,\mathrm{~kg},2  kg\mathrm{~kg}), and 3 kg : - Positions: (0,4),(4,0),(4,4)(0,4),(4,0),(4,4) - (x^{-}=(4 ⋅\cdot0+2 ⋅\cdot4+3 ⋅\cdot4) /(4+2+3)=(0+8+12) / 9=20 / 9  m\mathrm{~m}). C. y -coordinate of COM of (1  kg,\mathrm{~kg},4  kg\mathrm{~kg}), and 3 kg : - Positions: (0,0),(0,4),(4,4)(0,0),(0,4),(4,4) - (y=(1.0+4.4+3.4) /(1+4+3)=(0+16+12) / 8=28 / 8=7 / 2  m\mathrm{~m}). D. y -coordinate of COM of 1 kg and 3 kg : - Positions: (0,0),(4,4)(0,0),(4,4) - (\bar{y}=(1.0+3.4) /(1+3)=12 / 4=3  m\mathrm{~m}). Thus, matching to options set: - (p) (7 / 2  m\mathrm{~m}), (q) (4 / 3  m\mathrm{~m}), (r) 3 m, (s) 20/9 m.
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