Match the following columns. Codes array llll A & B & C & D array

The potential energy of satellite at distance $r$ from earth is $U=\frac{-G M m}{r}$ So, it is always negative as it is due to attractive gravitation force of earth's field. The kinetic energy of satellite is $K=\frac{G M m}{2 r}$ It is always positive. The total energy of satellite is $$\begin{aligned} \mathrm{TE} & =K+U=\frac{G M m}{2 r}-\frac{G M m}{r} \\ & =-\frac{G M m}{2 r} \end{aligned}$$ which is negative. The gravitation potential energy of satellite at infinity is $U=-\frac{G M m}{r}=-\frac{G M m}{\infty}=0$ So, the correct match is $\mathrm{A} \rightarrow$\mathrm{II}$, \mathrm{B} \rightarrow$\mathrm{II}$, \mathrm{C} \rightarrow$\mathrm{I}$, \mathrm{D} \rightarrow$ III. No option is correct.