Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsGravitation

What is the time-period of revolution of the moon in days, given that ( k = 10⁻¹³ , m ⁻³ ) and the moon is at a distance of ( 3.84 10^5 ) km from the Earth?

Options

  1. A27.3 days
  2. B30.2 days
  3. C29.5 days
  4. D31.7 days

Correct answer

A. 27.3 days

Step-by-step solution

Correct Option is : (A) 27.3 days

Practice Gravitation on Quantrex Academy →

More from Gravitation

The amount of work done to raise a mass ' m ' from the surface of the Earth to a height equal to the radius of the Earth ' R ', will be : 2026Two planets P₁ and P₂ with equal mass have radii R₁ and R₂ , respectively, where R₂= R₁ 2 . The escape speeds of P₁ and P₂ are v₁ and v₂ , respectively. Then v₂ v₁ is : 2026In a solar system, the time-period of revolution of a planet tracing a circular orbit of radius R is proportional to : 2026The radius of Martian orbit around the Sun is about 4 times the radius of the orbit of Mercury. The Martian year is 687 Earth days. Then which of the following is the length of 1 y 2025A body weighs 48 N on the surface of the earth. The gravitational force experienced by the body due to the earth at a height equal to one-third the radius of the earth from its sur 2025The escape velocity for earth is v . A planet having 9 times mass that of earth and radius, 16 times that of earth, has the escape velocity of: 2024The mass of a planet is 1 10 th that of the earth and its diameter is half that of the earth. The acceleration due to gravity on that planet is: 2024An object of mass 100 kg falls from point A to B as shown in figure. The change in its weight, corrected to the nearest integer is ( R_E is the radius of the earth) 2024 Full Gravitation list All NEET PYQs