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NEET2018PhysicsGravitationActual

A satellite is moving with a constant speed v in a circular orbit about the earth. An object of mass m is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is

Options

  1. A1 2 m v^2
  2. Bm v^2
  3. C1 3 m v^2
  4. D2 3 m v^2

Correct answer

B. m v^2

Step-by-step solution

Escape speed, v_e= 2 orbital speed = 2 v Kinetic energy of the object at the time of ejection = 1 2 m v_e^2= 1 2 m( 2 v)^2=m v^2

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