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NEET2002PhysicsGravitationActual

If v₀ be the orbital velocity of a satellite in a circular orbit close to the earth's surface and v_e is the escape velocity from the earth, then relation between the two is

Options

  1. Av_o=v_e
  2. Bv_e= 3 v₀
  3. Cv_e= 2 v₀
  4. Dv_e=2 v_o .

Correct answer

C. v_e= 2 v₀

Step-by-step solution

Orbital velocity of satellite =v₀ and escape velocity from the earth =v_e . We have orbital velocity (v₀ )= g R and escape velocity (v_e )= 2 g R Therefore ratio of orbital velocity to escape velocity v_o v_e = g R 2 g R = 1 2 or v_e= 2 v₀ .

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