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NEET2005PhysicsGravitationActual

Radius of orbit of satellite of earth is R . Its kinetic energy is proportional to

Options

  1. A1 R
  2. B1 R
  3. CR
  4. D1 R^ 3 / 2

Correct answer

A. 1 R

Step-by-step solution

Kinetic energy of the satellite KE = 1 2 m v₀^2 ...(1) where v₀= G M R Now putting the value of v₀ is eq. (1), we get KE = 1 2 m ( G M R )^2= 1 2 m G M R Hence, KE 1 R

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