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NEET
Exam
NEET
Subject
Physics
Chapter
Mechanical Properties of Fluids

NEET · Physics · Mechanical Properties of Fluids

Given below are two statements: one is labelled as Assertion (A)...

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Two spheres of the same material and radii RR and 2R2R fall through the same viscous liquid. When they attain their respective terminal velocities, the ratio of the viscous drag forces on them is 1:81 : 8.

Reason (R): The viscous drag force on a sphere moving at its terminal velocity is directly proportional to the cube of its radius.

In the light of the above statements, choose the most appropriate answer from the options given below.

Options

  1. ABoth (A) and (R) are correct and (R) is the correct explanation of (A)
  2. BBoth (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. C(A) is correct but (R) is not correct
  4. D(A) is not correct but (R) is correct

Correct answer

A. Both (A) and (R) are correct and (R) is the correct explanation of (A)

Step-by-step solution

According to Stokes' law, the viscous drag force is given by Fv=6πηrvF_v = 6\pi\eta r v.

The terminal velocity vtv_t of a sphere of radius rr and density ρ\rho falling in a liquid of density σ\sigma and viscosity η\eta is given by vt=29r2(ρ−σ)gηv_t = \dfrac{2}{9}\dfrac{r^2(\rho - \sigma)g}{\eta}.

Therefore, the terminal velocity is directly proportional to the square of the radius (vt∝r2v_t \propto r^2).

Substituting this into Stokes' law, we get Fv∝r(r2)⇒Fv∝r3F_v \propto r(r^2) \Rightarrow F_v \propto r^3.

Thus, the Reason is correct.

For two spheres of radii RR and 2R2R, the ratio of their viscous drag forces at terminal velocity will be R3:(2R)3=1:8R^3 : (2R)^3 = 1 : 8.

Thus, the Assertion is also correct, and the Reason is the correct explanation for the Assertion.

Answer: Both (A) and (R) are correct and (R) is the correct explanation of (A)
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