An object floats in water with 10 % of its volume outside and in oil 30 % of its volume outside. The specific gravity of the oil is

Step-by-step solution

Let V be the volume of an object. When the object is floating in the liquid, then Weight of the object = Weight of the liquid displaced Divide (i) by (ii), we get 1= 0.9 _ water 0.7 _ oil or _ oil _ water = 0.9 0.7 = 9 7 Specific gravity of the oil = _ oil = 9 7 _ water =1.3