An object floats in water with 10 \% of its volume outside and in...

An object floats in water with

10 \%

of its volume outside and in oil

30 \%

of its volume outside. The specific gravity of the oil is

Options

A $1.3$
B $0.33$
C $2$
D $7$

Correct answer

A. $1.3$

Step-by-step solution

Let

V

be the volume of an object. When the object is floating in the liquid, then Weight of the object = Weight of the liquid displaced Divide (i) by (ii), we get

1=\frac{0.9 \rho_{\text{water }}}{0.7 \rho_{\text{oil }}} \quad

\quad \frac{\rho_{\text{oil }}}{\rho_{\text{water }}}=\frac{0.9}{0.7}=\frac{9}{7}

Specific gravity of the oil

=\rho_{\text{oil }}=\frac{9}{7} \times \rho_{\text{water }}=1.3

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