If T is the surface tension of the liquid, the change in surface energy by splitting a liquid drop of radius R into 125 droplets of radius r is

Step-by-step solution

As volume of 125 droplets = Volume of the drop 125 4 3 r^3= 4 3 R^3 or 125 r^3=R^3 or r= R 5 The surface area of the drop =4 R^2 and the surface area of 125 droplets =125 (4 r^2 )=125 (4 ( R 5 )^2 )=20 R^2 aligned The increase in surface area & =20 R^2-4 R^2 & =16 R^2 aligned The change in surface energy = Surface tension increase in surface area =T 16 R^2=16 R^2 T