NEET2007PhysicsMechanical Properties of FluidsActual
Work of (3.0 10⁻⁴ ) joule is required to be done in increasing the size of a soap film from (10 ~cm 6 ~cm ) to (10 ~cm 11 ~cm ). The surface tension of the film is
Options
- A(5 10⁻² ~N / m )
- B(3 10⁻² ~N / m )
- C(1.5 10⁻² ~N / m )
- D(1.2 10⁻² ~N / m )
Correct answer
B. (3 10⁻² ~N / m )
Step-by-step solution
Surface tension, (S= work done increase in area ) As the soap film has two surfaces. ( aligned S & = 3.0 10⁻⁴ ~J 2 (10 11-10 6) 10⁻⁴ ~m ^2 & =3 10⁻² ~N / m . aligned )