NEET2004PhysicsMechanical Properties of FluidsActual
A sphere of mass M and radius R is falling in a viscous fluid. The terminal velocity attained by the falling object will be proportional to
Options
- AR^2
- BR
- C1 / R
- D1 / R^2 .
Correct answer
A. R^2
Step-by-step solution
Stoke's law : 6 R v= 4 3 R^3( - ) g v R^2 . As M is given, = M 4 3 R^3 But as R^3 increases, M also increases and is a constant. also is a constant. v , the terminal velocity R^2 .