If ratio of terminal velocity of two drops falling in air is 3: 4 , then what is the ratio of their surface area?

Step-by-step solution

Terminal velocity is given by v= 2 r^2( - ) 9 g where, r= radius of drop, = density of medium of drop, = density of surrounding medium = coefficient of viscocity of drop medium. v r ^2 , we know area of drop r ^2 v A (area) v ₁ v ₂ = A ₁ ~A ₂ = 3 4 A ₁ ~A ₂ = 3 4