A solid floats with 1 / 4 th of its volume above the surface of water, the density of the solid is

Step-by-step solution

Let V and be volume and density of solid respectively and ^ be the density of water i.e., p ^ =10^3 ~kg ~m ⁻³ Weight of body = V g Volume of solid body outside water = V / 4 Volume of solid body inside water = V - V / 4=3 ~V / 4 Weight of water displaced by solid = 3 ~V 4 10^3 g As solid body is floating, then Weight of body = Weight of water displaced by it aligned V g & = 3 ~V 4 10^3 ~g & = 3 4 1000=750 kgm ⁻³ aligned