1 ~g of steam is sent into 1 ~g of ice. At thermal equilibrium, the resultant temperature of mixture is

Step-by-step solution

Heat required to melt 1 ~g of ice at 0^ C to water at 0^ C =1 80 cal . Heat required to raise temperature of 1 ~g of water from 0^ C to 100^ C =1 1 100=100 cal . Total heat required for maximum temperature of 100^ C =80+100=180 cal . As one gram of steam gives 540 cal of heat when it is converted to water at 100^ C , therefore, temperature of the mixture =100^ C .