NEET2012PhysicsThermal Properties of MatterActual
Two conductors having same width and length, thickness d₁ and d₂ , thermal conductivity K₁ and k₂ are placed one above the another. Find the equivalent thermal conductivity.
Options
- A(d₁+d₂ ) (K₁ d₂+K₂ d₁ ) 2 (K₁+K₂ )
- B(d₁-d₂ ) (K₁ d₂+K₂ d₁ ) 2 (K₁+K₂ )
- CK₁ d₁+K₂ d₂ d₁+d₂
- DK₁+K₂ d₁+d₂
Correct answer
C. K₁ d₁+K₂ d₂ d₁+d₂
Step-by-step solution
Let t be the width and L be the length of each conductor. Effective thermal resistance, R_p= R₁ R₂ R₁+R₂ R= L K A where k= thermal conductivity L A K_ e q = L K₁ A₁ L K₂ A₂ L K₁ A₁ + L K₂ A₂ 1 K_ e q (A₁+A₂ ) = 1 K₂ A₂+K₁ A₁ K_ e q = K₁ A₁+K₂ A₂ A₁ A₂ = K₁ d₁ t+K₂ d₂ t d₁ t+d₂ t = K₁ d₁+K₂ d₂ d₁+d₂