Three moles of an ideal monoatomic gas undergoes a cyclic process as shown in the figure. The temperature of the gas in different states marked as 1, 2, 3 and 4 are $400 \mathrm{~K}, 700 \mathrm{~K}, 2500 \mathrm{~K}$ and $1100 \mathrm{~K}$ respectively. The work done by the gas during the process 1-2-3-4-1 is (universal gas constant is $R$ )

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Three moles of an ideal monoatomic gas undergoes a cyclic process as shown in the figure. The temperature of the gas in different states marked as 1, 2, 3 and 4 are

400 \mathrm{~K}, 700 \mathrm{~K}, 2500 \mathrm{~K}

and

1100 \mathrm{~K}

respectively. The work done by the gas during the process 1-2-3-4-1 is (universal gas constant is

R

)

Three moles of an ideal monoatomic gas undergoes a cyclic process as shown in the figure. The temperature of the gas in

Quantrex Academy · Accepted Answer

Correct answer: A. 1650 R

We knows d Q=d u+d w and we also known d u=0 for cyclio process so that d Q=d w Here, in given condition the work done during is a basic process aligned & w_ 2-3 =P_2 (v_3-v_2) & w_ 4-1 =p_1 (v_1-v_4) aligned Total work done =p_2 (v_3-v_2)+p_1 (v_1-v_4) From gas equationp V=n R T=(3 × T)/(2)Hence, total work done aligned & =(3 R)/(2)(400+2500-700-1100) & =(3)/(2)R(2900-1800) & = 3 2 R(1100)=(3300 R)/(2) & =1650 R aligned

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