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NEET
Exam
NEET
Subject
Physics
Chapter
Thermodynamics

NEET · Physics · Thermodynamics

A graph drawn between absolute temperature and volume of 3 moles of...

A graph drawn between absolute temperature and volume of 3 moles of helium gas as shown in the figure. If 5cal5 \mathrm{cal} of heat is used in the process, then the work done is A graph drawn between absolute temperature and volume of 3 moles of helium gas as shown in the figure. If 5 cal of heat

Options

  1. A21.0 J
  2. B8.4 J
  3. C12.6 J
  4. D6.2 J

Correct answer

B. 8.4 J

Step-by-step solution

In given graph, V \propto T \Rightarrow VT= constant \frac{V}{T}=\text{ constant }Hence, process is a constant pressure process.  So, \text{ So, }\DeltaQ=nCp\DeltaT and \DeltaW=p\DeltaV=nR\DeltaT=nR⋅ΔQnCp=ΔQR52R=25×\DeltaQ=2cal=2×4.2 J=8.4 J\begin{aligned} \DeltaQ= & n C_p \DeltaT \text{ and } \DeltaW=p \DeltaV=n R \DeltaT=n R \cdot \frac{\Delta Q}{n C_p}\\ = & \frac{\Delta Q R}{\frac{5}{2} R}=\frac{2}{5} \times \DeltaQ=2 \mathrm{cal}=2 \times4.2 \mathrm{~J}=8.4 \mathrm{~J} \end{aligned}$$
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