In the given pressure (P) - absolute temperature (T) graph of an ideal gas, the relation between volumes V_1, V_2, V_3 and V_4 is

Correct answer: D. V_1 < V_2 < V_3 < V_4 From the ideal gas equation aligned & PV=n · RT & P T = C V & V= C P / T 1 slop of the graph aligned Hence, V_1 V_2 V_3 V_4

NEET

Exam: NEET
Subject: Physics
Chapter: Thermodynamics

NEET · Physics · Thermodynamics

In the given pressure (P) - absolute temperature (T) graph of an...

In the given pressure

(\mathrm{P})

- absolute temperature

(\mathrm{T})

graph of an ideal gas, the relation between volumes

V_1, V_2, V_3

and

\mathrm{V}_4

In the given pressure (P) - absolute temperature (T) graph of an ideal gas, the relation between volumes V_1, V_2, V_3

Options

A $V_1=V_2=V_3=V_4$
B $V_1>V_2>V_3>V_4$
C $V_1>V_2>V_3 < V_4$
D $\mathrm{V}_1 < \mathrm{V}_2 < \mathrm{V}_3 < \mathrm{V}_4$

Correct answer

D. $\mathrm{V}_1 < \mathrm{V}_2 < \mathrm{V}_3 < \mathrm{V}_4$

Step-by-step solution

From the ideal gas equation

\begin{aligned}& \mathrm{PV}=\mathrm{n} \cdot \mathrm{R}T \\ & \frac{\mathrm{P}}{\mathrm{T}}=\frac{\mathrm{C}}{\mathrm{V}}\\ & \mathrm{V}=\frac{\mathrm{C}}{\mathrm{P} / \mathrm{T}} \propto \frac{1}{\text{ slop of the graph }} \end{aligned}

Hence,

\mathrm{V}_1 \lt \mathrm{V}_2 \lt \mathrm{V}_3 \lt \mathrm{V}_4

Practice Thermodynamics on Quantrex Academy →

More from Thermodynamics