The figure shows the graph of (pV)/(T) versus p for 2 × 10 ^ - 4 kg...

The figure shows the graph of $\dfrac{pV}{T}$ versus $p$ for $2 \times {10}^{- 4}kg$ of hydrogen gas at two different temperatures, where $p, V$ and $T$ represents pressure, volume and temperature respectively.Then, the value of $\dfrac{pV}{T},$ where the curve meet on the vertical axis, is

The figure shows the graph of (pV)/(T) versus p for 2 × 10 ^ - 4 kg of hydrogen gas at two different temperatures,

Options

A $\dfrac{R}{5}$
B $\dfrac{2R}{3}$
C $\dfrac{R}{10}$
D $\dfrac{R}{15}$

Correct answer

C. $\dfrac{R}{10}$

Step-by-step solution

Number of $moles$ in $2 \times {10}^{- 4}kg$

$\mu = \dfrac{Massofhydrogeningram}{Molecularmass}$

$= \dfrac{2 \times {10}^{- 4} \times {10}^{3}}{2}$

$= 0 . 1mole$

$∴ pV = \muRT$

$\dfrac{pV}{T} = \muR = 0 . 1 \times R = \dfrac{R}{10}$

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