An ideal gas is taken through the cycle A B C A , as shown in the figure. If the net heat supplied to the gas in the cycle is 5 ~J , the work done by the gas in the process C A is,

Step-by-step solution

Net work done by a gas, array ll W_ A B =p V=10 (2-1)=10 ~J W_ B C =0 & (as V= constant) array From first law of thermodynamics, we have, Q= W+ U U=0 (process A B C A is cyclic) Therefore, Q= W_ A B + W_ B C + W_ C A aligned W_ C A & = ( Q-W_ A B -W_ B C ) & =(5-10-0) J =-5 ~J aligned