List I describes thermodynamic processes in four different systems. List II gives the magnitudes (either exactly or as a close approximation) of possible changes in the internal energy of the system due to the process. List-I List-II (I) 10 - 3 kg of water 100 ° C is converted to steam at the same temperature, at a pressure of 10 5 Pa . The volume of the system changes from 10 - 6 m 3 to 10 - 3 m 3 in the process. La

Step-by-step solution

(I) According to the first law of thermodynamics, ∆ Q = ∆ U + W ⇒ ∆ U = ∆ Q - W ⇒ U = M L - P Δ V = 10 - 3 × 2250 - 10 2 kP × 10 - 3 - 10 - 6 m 3 = 2 . 25 kJ - 0 . 1 kJ = 2 . 15 kJ Therefore, I-P (II) For isobaric process, V 1 V 2 = T 1 T 2 ⇒ T 2 = 3 × 500 = 1500 K Now the change in the internal energy will be, ∆ U = n C V ∆ T = 0 . 2 × 5 2 × 8 × 1000 = 4 kJ Therefore, II-R (III) For adiabatic expansion of monoatomic gas γ = 5 3 P 1 V 1 γ = P 2 V 2 γ ⇒ 2 kPa × V 0 5 3 = P 2 × V 0 8 5 3 ⇒ P 2 = 64 kPa Now the change