Two moles of an ideal gas undergo a cyclic process A B C A represented on a Pressure-Temperature ( P-T ) diagram. The cycle forms a right-angled triangle with vertices at A(300 K , 1 atm ) , B(600 K , 1 atm ) , and C(300 K , 0.5 atm ) . The work done by the gas during the isobaric segment of the cycle is:

Step-by-step solution

The isobaric (constant pressure) segment of the cycle is the process A B , where the pressure remains constant at 1 atm . During this process, the temperature increases from T_A = 300 K to T_B = 600 K . The work done by an ideal gas during an isobaric process is given by: W = P V = nR T Given n = 2 moles, the change in temperature is T = 600 K - 300 K = 300 K . Substituting the values: W = 2 R 300 = 600 R Calculating the area of the triangle on the P-T graph ( 75 ) does not give the work done, and using n=1 gives t