An ideal gas is compressed from an initial volume V_ 0 to a final...

The slope of a P-V curve is given by $\dfrac{dP}{dV}$.

For an isothermal process, the slope is $-\dfrac{P}{V}$.

For an adiabatic process, the slope is $-\gamma\dfrac{P}{V}$.

Since $\gamma > 1$, the adiabatic curve is steeper than the isothermal curve.

During compression, the volume decreases. Starting from the same initial state, the steeper adiabatic curve will rise more rapidly than the isothermal curve. Therefore, the adiabatic curve will lie above the isothermal curve on the P-V diagram, reaching a higher final pressure.

Since curve A ends at a higher pressure than curve B, curve A represents the adiabatic process and curve B represents the isothermal process.

Answer: Curve A is adiabatic and curve B is isothermal