A reversible engine converts one-sixth of the heat input into work. When the temperature of the sink is reduced by 62^ C , the efficiency of the engine is doubled. The temperatures of the source and sink are

Step-by-step solution

₁=1- T_L T_H = W Q₁ = 1 6 or 5 T_H-6 T_L=0 ₂=1- T_L-62 T_H =2 ₁= 1 3 (Given) 1- 1 3 = T_L-62 T_H or 2 T_H-3 T_L=-186 Solving (i) and (ii), we get aligned & T_H=372 ~K =99^ C & T_L= 5 6 T_H= 5 6 372 ~K =310 ~K =37^ C aligned