An engine is working. It takes 100 calories of heat from source and leaves 80 calories of heat to sink. If the temperature of source is 127^ C , then temperature of sink is

Step-by-step solution

Heat taken from source Heat left to sink aligned & Q₁=100 cal & Q₂=80 cal aligned efficiency of the engine aligned =1- Q₂ Q₁ & =1- 80 100 & =20 % aligned Temperature of the source T₁=127^ C =400 ~K Temperature of the sink T₂= ? We know that aligned & =1- T₂ T₁ 0.2 & =1- T₂ 400 T₂ 400 & =1-0.2=0.8 T₂ & =320 ~K =47^ C aligned