NEET2010PhysicsThermodynamicsActual
1 mole of an ideal gas at an initial temperature of T ~K does 6 R joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5 / 3 , then final temperature of the gas will be
Options
- A(T-4) K
- B(T+4) K
- C(T-2.4) K
- D(T+2.4) K
Correct answer
A. (T-4) K
Step-by-step solution
Work done by gas in adiabatic process, array rlrl & & W & = n R (T_i-T_f ) -1 & 6 R & = 1 R (T-T₂ ) ( 5 3 -1 ) & or & 6 & = T-T₂ 2 / 3 & or & T & -T₂=4 or T₂=(T-4) K array