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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Physics
Chapter
Kinetic Theory of Gases

JIPMER 2016 · Physics · Kinetic Theory of Gases

Two different isotherms representing the relationship between...

Two different isotherms representing the relationship between pressure pp and volume VV at a given temperature of the same ideal gas are shown for masses m1m_1 and m2m_2, then Two different isotherms representing the relationship between pressure p and volume V at a given temperature of the

Options

  1. ANothing can be predicted
  2. Bm1<m2m_1 \lt m_2
  3. Cm1=m2m_1=m_2
  4. Dm1>m2m_1 \gt m_2

Correct answer

B. m1<m2m_1 \lt m_2

Step-by-step solution

∵pV=nRT=mMRT\because \quad p V=n R T=\frac{m}{M} R T For m1,p=m1M⋅RTV1m_1, \quad p=\frac{m_1}{M} \cdot \frac{R T}{V_1}...(i) For m2,p=m2M⋅RTV2m_2, \quad p=\frac{m_2}{M} \cdot \frac{R T}{V_2}....(ii) From Eqs. (i) and (ii), we get m1M⋅RTV1=m2M⋅RTV2⇒m1V1=m2V2\frac{m_1}{M} \cdot \frac{R T}{V_1}=\frac{m_2}{M} \cdot \frac{R T}{V_2} \Rightarrow \frac{m_1}{V_1}=\frac{m_2}{V_2} Thus, V∝m∵V2>V1∴m2>m1\begin{aligned} & \text{ Thus, } \quad V \propto m \\ & \because \quad V_2 > V_1 \\ & \therefore \quad m_2 > m_1 \\ & \end{aligned}$$
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