If the ratio of specific heat of gas γ = (C_p)/(C_v) , then the value of C_p in terms of γ and gas constant R is

Correct answer: A. (γ R)/(γ - 1) Given γ = (C_p)/(C_v) Using Mayer's relation, C_p - C_v = R Substituting C_v = (C_p)/(γ) into the relation: C_p - (C_p)/(γ) = R C_p ( (γ - 1)/(γ) ) = R C_p = (γ R)/(γ - 1) Answer: (γ R)/(γ - 1)

MHT CET 202625 AprilEvening Shift

Exam: MHT CET
Year: 2026
Date: 25 April
Shift: Evening Shift
Subject: Physics
Chapter: Kinetic Theory of Gases

MHT CET 2026 · 25 April · Evening Shift · Physics · Kinetic Theory of Gases

If the ratio of specific heat of gas γ = (C_p)/(C_v) , then the...

If the ratio of specific heat of gas

\gamma = \dfrac{C_p}{C_v}

, then the value of

C_p

in terms of

\gamma

and gas constant

R

Options

A $\dfrac{\gamma R}{\gamma - 1}$
B $\dfrac{R}{\gamma - 1}$
C $\dfrac{(\gamma - 1)R}{\gamma}$
D $\dfrac{R}{\gamma}$

Correct answer

A. $\dfrac{\gamma R}{\gamma - 1}$

Step-by-step solution

Given

\gamma = \dfrac{C_p}{C_v}

Using Mayer's relation,

C_p - C_v = R

Substituting

C_v = \dfrac{C_p}{\gamma}

into the relation:

C_p - \dfrac{C_p}{\gamma} = R

C_p \left( \dfrac{\gamma - 1}{\gamma} \right) = R

C_p = \dfrac{\gamma R}{\gamma - 1}

Answer:

\dfrac{\gamma R}{\gamma - 1}

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