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NEET
Exam
NEET
Subject
Physics
Chapter
Waves and Sound

NEET · Physics · Waves and Sound

A sound source S is moving along a straight track with speed v ,...

A sound source S is moving along a straight track with speed vv, and is emitting sound of frequency v0{v}_{0}.An observer is standing at a finite distance, at the point O,O, from the track. The time variation of frequency heard by observer is best represented by : (to represents the instant when the distance between the source and observer is minimum)A sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observerA sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observerA sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observerA sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observerA sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observerA sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observer

Options

  1. AWhy does SO 3 act as an electrophile?
  2. BWhy does SO 3 act as an electrophile?
  3. CWhy does SO 3 act as an electrophile?
  4. DWhy does SO 3 act as an electrophile?

Correct answer

B. Why does SO 3 act as an electrophile?

Step-by-step solution

A sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observer

Observed frequency will be v=Vsound+Vcos\thetaVsoundv0v = \dfrac{{V}_{\text{sound}} + Vcos\text{\theta}}{{V}_{\text{sound}}}{v}_{0}

Using this formula we can say that observed frequency will decrease continuously and it becomes equal to original frequency when \theta=90°\text{\theta} = 90 °. So correct graph is

A sound source S is moving along a straight track with speed v , and is emitting sound of frequency v _ 0 .An observer 

 

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