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NEET2011PhysicsWaves and SoundActual

If man were standing unsymmetrically between parallel cliffs, claps his hands and starts hearing a series of echoes at intervals of 1 ~s . If speed of sound in air is 340 ~m ~s ⁻¹ , the distance between two cliffs would be

Options

  1. A340 ~m
  2. B510 ~m
  3. C170 ~m
  4. D680 ~m

Correct answer

B. 510 ~m

Step-by-step solution

Let x be distance of person from one cliff and y be distance of person from 2^ nd cliff. Let aligned y>x & x & +x=v t₁=340 1=340 x & =170 ~m y+y & =v t₂=340 2=680 y & =340 ~m . aligned Distance between two cliffs =x+y=170+340=510 ~m

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