NEET2008PhysicsWaves and SoundActual
Two closed organ pipes of length (100 ~cm ) and (101 ~cm ) produces 16 beats in (20 sec ). When each pipe is sounded in its fundamental mode calculate the velocity of sound.
Options
- A(303 ~ms ⁻¹ )
- B(332 ~ms ⁻¹ )
- C(323.2 ~ms ⁻¹ )
- D(300 ~ms ⁻¹ ).
Correct answer
C. (323.2 ~ms ⁻¹ )
Step-by-step solution
Frequency of fundamental mode of vibrations of 1^ st closed organ pipe, From question, v₁-v₂= 16 20 aligned & v 4 100 - v 4 101 = 16 20 & v 4 [ 1 100 - 1 101 ]= 16 20 & v 4 [ 101-100 101 100 ]= 16 20 v 4 1 101 100 = 16 20 & v= 16 101 4 100 20 =32320 ~cm / s . & =323.2 ~m / s . aligned