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A closed organ pipe of length 20 cm is sounded with tuning fork in resonance. What is the frequency of tuning fork? (v=332 ~m / s )

Options

  1. A300 Hz
  2. B350 Hz
  3. C375 Hz
  4. D415 Hz

Correct answer

D. 415 Hz

Step-by-step solution

Key Idea : When length of air column is 4 , then first resonance occurs. If we adjust the length of air-column in closed organ pipe as such its any natural frequency equals to the frequency of tuning fork, then the amplitude of forced vibrations of air-column increases very much. This is the state of resonance. At first resonance l= 4 So, frequency of tuning fork f= v = v 4 l Given, l=20 ~cm =0.2 ~m , v=332 ~m / s Hence, f= 332 4 0.2 =415 ~Hz

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