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NEETPhysicsElectrostatics

Statement-I : Work done by electric field on moving a positive charge on an equipotential surface is always zero. and Statement-II : Electric lines of forces are perpendicular to equipotential surface.

Options

  1. AStatement-I is True, Statement-II is True ; Statement-II is a correct explanation for Statement-I.
  2. BStatement-I is True, Statement-II is True ; Statement-II is not a correct explanation for Statement-I.
  3. CStatement-I is True, Statement-II is False.
  4. DStatement-I is False, Statement-II is True.

Correct answer

A. Statement-I is True, Statement-II is True ; Statement-II is a correct explanation for Statement-I.

Step-by-step solution

- Statement-I: This is true. The work done by an electric field on a charge moving on an equipotential surface is always zero because the potential difference between any two points on the surface is zero. Work done is given by: (W=q V ) - Statement-II: This is also true. Electric field lines are always perpendicular to equipotential surfaces. If they were not, there would be a component of the electric field along the surface, which would result in a change in potential (and hence work would be done when moving al

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