MHT CET Medical202626 April 2026Morning ShiftPhysicsElectrostaticsActual

The electric potential 'V' as a function of distance x (in metre) is V = 4x^2 + 6x - 8 volt. Electric field at x = 2 m is

Options

A-11 V/m
B-22 V/m
C-16 Vm
D-8 V/m

Correct answer

B. -22 V/m

Step-by-step solution

The relation between electric field E and electric potential V is given by E = - dV dx . Given V = 4x^2 + 6x - 8 . Differentiating with respect to x : dV dx = d dx (4x^2 + 6x - 8) = 8x + 6 Therefore, E = -(8x + 6) . At x = 2 m: E = -(8(2) + 6) = -(16 + 6) = -22 V/m . Answer: -22 V/m

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