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MHT CET 202626 AprilMorning Shift

Exam: MHT CET
Year: 2026
Date: 26 April
Shift: Morning Shift
Subject: Physics
Chapter: Electrostatics

MHT CET 2026 · 26 April · Morning Shift · Physics · Electrostatics

The electric potential 'V' as a function of distance x (in metre)...

The electric potential 'V' as a function of distance x (in metre) is

V = 4x^2 + 6x - 8

volt. Electric field at

x = 2

m is

Options

A $-11\ \text{V/m}$
B $-22\ \text{V/m}$
C $-16\ \text{Vm}$
D $-8\ \text{V/m}$

Correct answer

B. $-22\ \text{V/m}$

Step-by-step solution

The relation between electric field

E

and electric potential

V

is given by

E = -\dfrac{dV}{dx}

.

Given

V = 4x^2 + 6x - 8

.

Differentiating with respect to

x

:

\dfrac{dV}{dx} = \dfrac{d}{dx}(4x^2 + 6x - 8) = 8x + 6

Therefore,

E = -(8x + 6)

.

At

x = 2

m:

E = -(8(2) + 6) = -(16 + 6) = -22\ \text{V/m}

.

Answer:

-22\ \text{V/m}

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