NEETPhysicsElectrostatics
A spherical conductor of radius (R=0.5, m ) carries a charge of (+8, C ). A point charge (q=-4, C ) is placed 2 meters away from the center of the sphere. 1. Statement 1: What is the electric field just outside the surface of the spherical conductor? 2. Statement 2: What is the electrostatic potential at the surface of the sphere? 3. Statement 3: Calculate the force on the point charge (q ).
Options
- A(2.88 10^5, N / C, 1.44 10^5, V ), (7.2, N )
- B(3.6 10^5, N / C, 2.88 10^5, V ), (9.6, N )
- C(2.88 10^5, N / C, 2.88 10^5, V ), (7.2, N )
- D(3.6 10^5, N / C, 1.44 10^5, V ), (9.6, N )
Correct answer
A. (2.88 10^5, N / C, 1.44 10^5, V ), (7.2, N )
Step-by-step solution
- Electric Field: Use (E= k Q R^2 ) just outside the spherical conductor. - Potential: The potential on the surface is (V= k Q R ). - Force on (q ) : Calculate using Coulomb' s law considering the distance from the charge (q ) to the center of the sphere.