NEETPhysicsElectrostatics
Electric potential on the surface of a uniformly charged solid sphere is V. Radius of the sphere is 1 m. Match the following two columns. ( array |c|l|c|l| & Column 1 & & Column 2 (a) & Electric potential at r= R 2 & (p) & V 4 (b) & Electric potential at r=2R & (q) & V 2 (c) & Electric field at r= R 2 & (r) & 3V 4 (d) & Electric field at r=2R & (s) & 11V 8 array )
Options
- Aa-p, b-s, c-r, d-q
- Ba-p, b-r, c-q, d-s
- Ca-s, b-q, c-q, d-p
- Da-q, b-q, c-r, d-s
Correct answer
C. a-s, b-q, c-q, d-p
Step-by-step solution
( aligned & V_ R / 2 = k Q 2 R^3 [3 R^2- ( R 2 )^2 ]= k Q 2 R^3 ( 11 R^2 4 ) & V_ R / 2 = 11 k Q 8 R = 11 ~V 8 ; V_s= k Q R & V_ 2 R = k Q 2 R = V 2 & E_ R / 2 = k Q R R^3 2 = k Q 2 R^2 = V 2 (R=1 m) & E_ 2 R = k Q (2 R)^2 = V 4 aligned )