Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsElectrostatics

Match the configurations of an electric dipole in List-I with their corresponding mechanical states in List-II. List-I List-II (A) Dipole parallel to a unidirectional non-uniform electric field (I) Net force is zero, torque is zero, stable equilibrium (B) Dipole antiparallel to a unidirectional non-uniform electric field (II) Net force is non-zero, torque is zero, stable equilibrium (C) Dipole perpendicular to a unif

Options

  1. A(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
  2. B(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  3. C(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  4. D(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Correct answer

D. (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Step-by-step solution

In a uniform electric field, the net force on a dipole is always zero. If the dipole is parallel to the field ( = 0^ ), the torque is zero and it is in stable equilibrium. If it is perpendicular ( = 90^ ), the torque is maximum and non-zero. In a non-uniform electric field, the net force is generally non-zero. If the dipole is parallel to the field ( = 0^ ), the torque is zero and it is in stable equilibrium. If it is antiparallel ( = 180^ ), the torque is zero and it is in unstable equilibrium. Matching these cond

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

The electric field at a point in a certain region of free space due to a charge Q is 0. The electric potential at that point is 2026A closed surface encloses n electric dipoles. The net electric flux through the closed surface is ( ₀ = permittivity of free space, q = charge) 2026A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 V . The electric field at its centre is 2026Four infinitely large planar charged sheets are placed parallel to each other as shown in Figure 1. Find the magnitude of electric field at point P. 2026The electric potential 'V' as a function of distance x (in metre) is V = 4x^2 + 6x - 8 volt. Electric field at x = 2 m is 2026A uniform electric field is given as E = 4 10^4 , j N/C . The flux of this field through a square of side 10 cm whose plane is parallel to the Y-Z plane is 2026Assume that the electric field E = 30 x^2 i exists in space. Then the potential difference V_A - V_O , where ' V_O ' is the potential at the origin and ' V_A ' is the potential at 2026Two point charges +8q and -2q are located at x=0 and x=L respectively. What is the location of a point on the x-axis from the origin, at which the net electric field due to these t 2026 Full Electrostatics list All NEET PYQs