Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NEETPhysicsElectrostatics

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The electric field at all points inside a uniformly charged hollow conducting sphere is zero. Reason (R): Any excess charge given to a hollow conducting sphere distributes uniformly throughout its inner volume. In the light of the above statements, choose the most appropriate answer from the option

Options

  1. ABoth Assertion and Reason are true and Reason is the correct explanation of Assertion.
  2. BBoth Assertion and Reason are true but Reason is not the correct explanation of Assertion.
  3. CAssertion is true but Reason is false.
  4. DAssertion is false but Reason is true.

Correct answer

C. Assertion is true but Reason is false.

Step-by-step solution

Assertion (A) is true because the electric field inside a conductor in electrostatic equilibrium is always zero. For a uniformly charged hollow conducting sphere, the field at all internal points ( r Reason (R) is false because any excess charge given to a conducting sphere (whether hollow or solid) resides entirely on its outer surface due to mutual repulsion of charges, not throughout its volume. Since the charge resides only on the surface, a Gaussian surface drawn inside encloses no net charge, leading to zero

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

The electric field at a point in a certain region of free space due to a charge Q is 0. The electric potential at that point is 2026A closed surface encloses n electric dipoles. The net electric flux through the closed surface is ( ₀ = permittivity of free space, q = charge) 2026A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 V . The electric field at its centre is 2026Four infinitely large planar charged sheets are placed parallel to each other as shown in Figure 1. Find the magnitude of electric field at point P. 2026The electric potential 'V' as a function of distance x (in metre) is V = 4x^2 + 6x - 8 volt. Electric field at x = 2 m is 2026A uniform electric field is given as E = 4 10^4 , j N/C . The flux of this field through a square of side 10 cm whose plane is parallel to the Y-Z plane is 2026Assume that the electric field E = 30 x^2 i exists in space. Then the potential difference V_A - V_O , where ' V_O ' is the potential at the origin and ' V_A ' is the potential at 2026Two point charges +8q and -2q are located at x=0 and x=L respectively. What is the location of a point on the x-axis from the origin, at which the net electric field due to these t 2026 Full Electrostatics list All NEET PYQs