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NEET2009PhysicsElectrostaticsActual

A wire of length l and mass m is bent in the form of a semicircle. The gravitational field intensity at the centre of semicircle is

Options

  1. AG m l along x -axis
  2. BG m l along y -axis
  3. C2 G m l^2 along y -axis
  4. D2 G m l^2 along x -axis

Correct answer

C. 2 G m l^2 along y -axis

Step-by-step solution

Consider two small elements each of length d l=r d symmetrically. r=l Resolve the elemental field intensities |d E₁ |= |d E₂ |d E=2 d E₁ = 2 G r d r^2 aligned & G = Gravitational constant & = Linear massdensity = m l aligned or d E= 2 G r ₀^ 90^ d = 2 G r = 2 G m l^2

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