NEET2008PhysicsElectrostaticsActual
Electric field at the centre of a uniformly charged semicircle of radius (a ) is
Options
- A( 2 ₀ a^2 )
- B( 4 ^2 ₀ a^2 )
- C( ^2 2 ₀ a )
- D( 2 ₀ a )
Correct answer
D. ( 2 ₀ a )
Step-by-step solution
Electric field intensity at O due to small elemental length d l of charged ring, aligned & d E= 1 4 ₀ d l a^2 = 1 4 ₀ a d a^2 & d E= 1 4 ₀ a d aligned Net electric field at centre O is aligned E= d E & = ₀^ 1 4 ₀ a d & = 4 ₀ a [- ]₀^ E & = 2 ₀ a . aligned