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NEET2008PhysicsElectrostaticsActual

A charge (q ) is uniformly distributed on a ring of radius (r ). A sphere of an equal radius is constructed with its centre lying on the periphery of the ring. The flux of electric field through the surface of the sphere will be

Options

  1. A( q ₀ )
  2. B( q 2 ₀ )
  3. C( q 3 ₀ )
  4. D( q 4 ₀ )

Correct answer

C. ( q 3 ₀ )

Step-by-step solution

Charge on ring q , centre of ring =O Centre of sphere =O^ Linear charge density of ring, = q 2 a Charge on arc A B of ring, aligned & q_ A B = ( arc A B)= 1 2 a q 2 a 3 & q_ A B =q / 3 aligned i.e., charge enclosed by sphere =q / 3 Flux coming out of sphere =q / 3 ₀ .

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