For the given input voltage waveform V _ in ( t ) , the output voltage waveform V _ 0 ( t ) , across the capacitor is correctly depicted by :

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Correct answer: A.

For the given input voltage waveform V _ in ( t ) , the output voltage waveform V _ 0 ( t ) , across the capacitor is

When first pulse is applied the potential across capacitor is given by $V = {V}_{0}\left(1 - {e}^{- \dfrac{t}{RC}}\right)$

When no pulse is applied, capacitor will discharge like $V = {V}_{0}^{'}{e}^{t / RC}$ when again, second pulse is applied $V = {V}_{0}\left(1 - {e}^{- \dfrac{t}{RC}}\right)$

Using all three equations the correct graph is :

For the given input voltage waveform V _ in ( t ) , the output...

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