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NEET
Exam
NEET
Subject
Physics
Chapter
Capacitance

NEET · Physics · Capacitance

In the circuit shown in figure ( E= 25 ~V, ~L= 2 H ), ( C= 60 μ ~F,...

In the circuit shown in figure (E=\mathrm{E}=25  V, L=\mathrm{~V}, \mathrm{~L}=2 H\mathrm{H}), (C=\mathrm{C}=60 \mu \mathrm{~F}, \mathrm{R}}_{1}=5 \Omega) and (\mathrm{R}}_{2}=10 \Omega). Switch S is closed at (t=\mathrm{t}=0). In the circuit shown in figure ( E= 25 ~V, ~L= 2 H ), ( C= 60 μ ~F, R _ 1 =5 ) and (R _ 2 =10 ). Switch S is closed at
(
Column IColumn II
(A)Current through R_1 at t=0(P)0
(B)Current through R_2 at t=0(Q)5 A
(C)Current through R_1 at t=∞\infty(R)2.5 A
(D)Current through R_2 at t=∞\infty(S)None of these
)

Options

  1. A(A \rightarrow P, B \rightarrow Q, C \rightarrow P, D \rightarrow R)
  2. B(\mathrm{A} \rightarrow \mathrm{Q}, \mathrm{B} \rightarrow \mathrm{P}, \mathrm{C} \rightarrow \mathrm{P}, \mathrm{D} \rightarrow \mathrm{R})
  3. C(\mathrm{A} \rightarrow \mathrm{Q}, \mathrm{B} \rightarrow \mathrm{P}, \mathrm{C} \rightarrow \mathrm{R}, \mathrm{D} \rightarrow \mathrm{P})
  4. D(\mathrm{A} \rightarrow \mathrm{P}, \mathrm{B} \rightarrow \mathrm{R}, \mathrm{C} \rightarrow \mathrm{P}, \mathrm{D} \rightarrow \mathrm{Q})

Correct answer

B. (\mathrm{A} \rightarrow \mathrm{Q}, \mathrm{B} \rightarrow \mathrm{P}, \mathrm{C} \rightarrow \mathrm{P}, \mathrm{D} \rightarrow \mathrm{R})

Step-by-step solution

At t=0I1=ER1=255=5AI2=0\begin{aligned} & \text{At } \mathrm{t}=\mathrm{0} \\ & I_1=\frac{E}{R_1}=\frac{25}{5}=5 \mathrm{ A} \\ & I_2=0\end{aligned}) At (\mathrm{t}=\infty) I1=0I2=ER2=2510=2.5A\begin{aligned} & I_1=0 \\ & I_2=\frac{E}{R_2}=\frac{25}{10}=2.5 \mathrm{ A} \end{aligned})
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