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NEET
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Physics
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Capacitance

NEET · Physics · Capacitance

Match List-I with List-II for the equivalent capacitance of...

Match List-I with List-II for the equivalent capacitance of different arrangements of three identical capacitors, each of capacitance CC.

List-IList-II
(A) Three capacitors connected in series(I) 3C3C
(B) Three capacitors connected in parallel(II) C3\dfrac{C}{3}
(C) Two capacitors in series, connected in parallel with the third(III) 2C3\dfrac{2C}{3}
(D) Two capacitors in parallel, connected in series with the third(IV) 3C2\dfrac{3C}{2}

Choose the correct answer from the options given below:

Options

  1. A(A) →\rightarrow (I), (B) →\rightarrow (II), (C) →\rightarrow (III), (D) →\rightarrow (IV)
  2. B(A) →\rightarrow (II), (B) →\rightarrow (I), (C) →\rightarrow (III), (D) →\rightarrow (IV)
  3. C(A) →\rightarrow (II), (B) →\rightarrow (IV), (C) →\rightarrow (I), (D) →\rightarrow (III)
  4. D(A) →\rightarrow (II), (B) →\rightarrow (I), (C) →\rightarrow (IV), (D) →\rightarrow (III)

Correct answer

D. (A) →\rightarrow (II), (B) →\rightarrow (I), (C) →\rightarrow (IV), (D) →\rightarrow (III)

Step-by-step solution

(A) For three identical capacitors in series, the equivalent capacitance CsC_s is given by:
1Cs=1C+1C+1C=3C⇒Cs=C3\dfrac{1}{C_s} = \dfrac{1}{C} + \dfrac{1}{C} + \dfrac{1}{C} = \dfrac{3}{C} \Rightarrow C_s = \dfrac{C}{3}

(B) For three identical capacitors in parallel, the equivalent capacitance CpC_p is:
Cp=C+C+C=3CC_p = C + C + C = 3C

(C) For two capacitors in series, their equivalent is C2\dfrac{C}{2}. When connected in parallel with the third capacitor, the total equivalent capacitance is:
Ceq=C2+C=3C2C_{eq} = \dfrac{C}{2} + C = \dfrac{3C}{2}

(D) For two capacitors in parallel, their equivalent is 2C2C. When connected in series with the third capacitor, the total equivalent capacitance is:
Ceq=2C×C2C+C=2C23C=2C3C_{eq} = \dfrac{2C \times C}{2C + C} = \dfrac{2C^2}{3C} = \dfrac{2C}{3}

Therefore, the correct match is (A) →\rightarrow (II), (B) →\rightarrow (I), (C) →\rightarrow (IV), (D) →\rightarrow (III).

Answer: (A) →\rightarrow (II), (B) →\rightarrow (I), (C) →\rightarrow (IV), (D) →\rightarrow (III)
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